If we set $F_moon/F_me = 1$ so the attraction is equal, her mass and the gravitational constant cancel out so we end up with $$ (M_moon / r^2_moon) / (M_me / r^2_me) = 1 $$ which we can rearrange to $$ r_me = r_moon sqrt(M_me/M_moon) $$ which is 0.011m, or 1.1cm
(My lemmy client doesn’t show latex markdown but hopefully at least some do so this looks less dogshit)
Edited to add: this also treats human beings like point masses, which is a less than useful approximation for close distances. The answer isn’t that you’d need to be nearly touching, it’s that your centers of mass would need to be nearly touching, ie your bodies would have to physically overlap
I personally don’t mind at all if open source projects want to sell a “pro” version for businesses, as long as it’s still open source. Selling priority troubleshooting and dev attention to issues to businesses seems like one of the less offensive ways to fund open source projects in a capitalist society, imo